Write The Following Equation Of The Circle In General Form That Will Satisfy The Given Conditions, 2. The Center Is At (-3,2), And The Circle Passes T

Write the following equation of the circle in general form that will satisfy the given conditions

2. the center is at (-3,2), and the circle passes through (4,-6).

 

Answer:

x² + y² + 6x - 4y - 100 = 0

Step-by-step explanation:

write the following equation of the circle in general form that will satisfy the given conditions  

2. the center is at (-3,2), and the circle passes through (4,-6).

first, find the radius

use distance formula (center to a point that the circle passes)

d = √(x2 - x1)² + (y2 -y1)²

d = √(4 - -3)² + (-6 - 2)²

d = √113

r = √113

Standard form: (x-h)² + (y-k)² = r²

where  h and k are the coordinates of the center of the circle

(x - -3)² + (y - 2)² = (√113)²

(x + 3)² + (y - 2)² = 113

x² + 6x + 9 + y² - 4y + 4 - 113 = 0

x² + y² + 6x - 4y - 100 = 0